How To Iterate Through A List Using XOR In Python

So I got the following code: telegram = '$00;02;A1;00000000*49' checksum = telegram[10:18] # is 00000000 for x in telegram[1:]: x = '{0:08b}'.format(i

Solution 1:

You can skip the conversion to a binary string using the function ord() on each character. For example:

>>> telegram = "$00;02;A1;00000000*49"
>>> ord(telegram[1]) ^ ord(telegram[2])
0

You can convert all the characters to ordinals with a list comprehension:

>>> [ord(n) for n in telegram[1:]] # all but first character...
[48, 48, 59, 48, 50, 59, 65, 49, 59, 48, 48, 48, 48, 48, 48, 48, 48, 42, 52, 57]

With tools in the standard library like functools.reduce and operator.xor you can XOR all the values together:

>>> import functools
>>> import operator
>>> functools.reduce(operator.xor,[ord(n) for n in telegram[1:]])
110
>>> format(110,'08b') # binary if needed
'01101110'