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Which Is The Best Way To Get A List Of Running Processes In Unix With Python?

I'm trying: import commands print commands.getoutput('ps -u 0') But it doesn't work on os x. os instead of commands gives the same output: USER PID %CPU %MEM VSZ RSS T

Solution 1:

This works on Mac OS X 10.5.5. Note the capital -U option. Perhaps that's been your problem.

import subprocess
ps = subprocess.Popen("ps -U 0", shell=True, stdout=subprocess.PIPE)
print ps.stdout.read()
ps.stdout.close()
ps.wait()

Here's the Python version

Python 2.5.2 (r252:60911, Feb 222008, 07:57:53) 
[GCC 4.0.1 (Apple Computer, Inc. build 5363)] on darwin

Solution 2:

If the OS support the /proc fs you can do:

>>>import os>>>pids = [int(x) for x in os.listdir('/proc') if x.isdigit()]>>>pids
[1, 2, 3, 6, 7, 9, 11, 12, 13, 15, ... 9406, 9414, 9428, 9444]
>>>

A cross-platform solution (linux, freebsd, osx, windows) is by using psutil:

>>>import psutil>>>psutil.pids()
[1, 2, 3, 6, 7, 9, 11, 12, 13, 15, ... 9406, 9414, 9428, 9444]    
>>>

Solution 3:

The cross-platform replacement for commands is subprocess. See the subprocess module documentation. The 'Replacing older modules' section includes how to get output from a command.

Of course, you still have to pass the right arguments to 'ps' for the platform you're on. Python can't help you with that, and though I've seen occasional mention of third-party libraries that try to do this, they usually only work on a few systems (like strictly SysV style, strictly BSD style, or just systems with /proc.)

Solution 4:

any of the above python calls - but try 'pgrep

Solution 5:

I've tried in on OS X (10.5.5) and seems to work just fine:

print commands.getoutput("ps -u 0")

UID   PID TTY           TIME CMD
0     1 ??         0:01.62 /sbin/launchd
0    10 ??         0:00.57 /usr/libexec/kextd

etc.

Python 2.5.1

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