Python - Efficient Way To Create 20 Variables?

I need to create 20 variables in Python. That variables are all needed, they should initially be empty strings and the empty strings will later be replaced with other strings. I ca

Solution 1:

Where is my mistake?

There are possibly three mistakes. The first is that 'variable_' + 'a' obviously isn't equal to 'variable_1'. The second is the quoting in the argument to exec. Do

forx in list:
    exec("variable_%s = ''" % x)

to get variable_a etc.

The third mistake is that you're not using a list or dict for this. Just do

variable = dict((x, '') for x in list)

then get the contents of "variable" a with variable['a']. Don't fight the language. Use it.

Solution 2:

I have the same question as others (of not using a list or hash), but if you need , you can try this:

for i in xrange(1,20):
    locals()['variable_%s' %i] = ''

Im assuming you would just need this in the local scope. Refer to the manual for more information on locals

Solution 3:

never used it, but something like this may work:

liste = ['a', 'b']
for item in liste:
    locals()[item] = ''