Numpy Equivalent Of If/else List Comprehension May 10, 2024 Post a Comment Is there a numpy way of doing n = [x-t if x > 0 else x for x in nps] similar to this n = np.array(a) n[np.abs(n) < t] = 0 something like this perhaps? n[n > 0] = n-tSolution 1: Can't test now, but trynp.where(n > 0, n - t, n) CopySee documentation Baca JugaIndex Column Values In 2d Array Using Array Of IndicesMatplotlib, How To Loop?Working With 2 Arrays With Different Lengths Numpy Python Share You may like these posts`numpy.mean` Used With A Tuple As `axis` Argument: Not Working With A Masked ArrayFastest Way To Find The Dot Product Of A Large Matrix Of VectorsFinding Relative Maximums Of A 2-d Numpy ArrayAverage Entries With Duplicate First Element In 2d Numpy Array Post a Comment for "Numpy Equivalent Of If/else List Comprehension"
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