Return A List Of The Paths Of All The Parts.txt Files

Write a function list_files_walk that returns a list of the paths of all the parts.txt files, using the os module's walk generator. The function takes no input parameters. def list

Solution 1:

You pretty much have it here--the only adjustments I'd make are:

• Make sure list_files is scoped locally to the function to avoid side effects.
• Use parameters so that the function can work on any arbitrary path.
• Return a generator with the yield keyword which allows for the next file to be fetched lazily.
• 'parts.txt' in dirpath could be error-prone if the filename happens to be a substring elsewhere in a path. I'd use endswith or iterate over the second item in the tuple that os.walk which is a list of all the items in the current directory, e.g. 'parts.txt' in dirnames.
• Along the same line of thought as above, you might want to make sure that your target is a file with os.path.isfile.

Here's an example:

import os

deffind_files_rec(path, fname):
    for dirpath, dirnames, files in os.walk(path):
        if fname in files:
            yieldf"{dirpath}/{fname}"if __name__ == "__main__":
    print(list(find_files_rec(".", "parts.txt")))